FINDING THE nth TERM IN A SEQUENCE
80Formula's for the nth term
Here I intend to look at what is known as the nth term sequence. In doing so we will look at some examples and find the nth term which is known in mathematical terms by a "u" followed by a subscript(small) "n".
So what exactly is the connection( the pattern) between the "n" and the "un".
If we take a closer look at the un we can see that it goes up in two's (2's).
(Position) U 1 2 3 4 5
( Term) Un 3 5 7 9 11
n x 2 2 4 6 8 10
3 + 2 = 5
5 + 2 = 7
7 + 2 = 9
9 + 2 = 11
Therefore we can write down that un = 2n, in other words we are doubling the number.
Looking again we may need to adjust that 2n slightly;
2n means 2 x n therefore,
2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
These are the numbers we have got after multiplyingn x 2, you will have noticed that they are 1 less in each case than the numbers in the unbracket, therefore we need to add on 1 in the formula.
Our formula now looks like this un = 2n + 1 (where the un is the nth term)
2 x n = ? + 1 = un
2 x 1 = 2 + 1 = 3
2 x 2 = 4 + 1 = 5
2 x 3 = 6 + 1 = 7
2 x 4 = 8 + 1 = 9
2 x 5 = 10 + 1 = 11
Answer:- un = 2n + 1
This is the type of question for the nth term, could be asked in an exam paper;
Find the nth term for the sequence; 2, 6, 10, 14, 18 ... (etc)?
To begin with we need to change this sequence into a table!
The "n" is the position and the “un” is the term.
The position simply represents the number of digits in a sequence, in the above there are "5" [ 2(which is 1), 6(which is 2), 10(which is 3), 14(which is 4), 18( finally this is number 5 )]
(Position) U 1 2 3 4 5
( Term) Un 2 6 10 14 18
n x 4 4 8 12 16 20
So what exactly is the connection (the pattern ) between the "n" and the "un", in this question?
If we take a closer look at the "un" we can see that it is going up in four's (4's).
2 + 4 = 6
6 + 4 = 10
10 + 4 = 14
14 + 4 = 18
Therefore we can write down that un = 4n (which means 4 x n)
4 x 1 = 4
4 x 2 = 8
4 x 3 = 12
4 x 4 = 16
4 x 5 = 20
These are the numbers we have got after multiplying n x 4, you will have noticed that there are 2 more in each case than the numbers in the un term, therefore we need to subtract 2 in the formula.
Our formula now looks like this; un = 4n - 2 (where the unis the nth term)
4 x n = ? - 2 = un
4 x 1 = 4 – 2 = 2
4 x 2 = 8 – 2 = 6
4 x 3 = 12– 2 = 10
4 x 4 = 16– 2 = 14
4 x 5 = 20– 2 = 18
Answer:- un = 4n - 2
In this example we need to find the nth term for this sequence;
Find the nth term for the sequence; 3, 6, 11, 18, 27 ... (etc)?
To begin with we need to change this sequence into a table!
This example is quite similar to the one above!!!!
LOOK CAREFULLY:-
The "n" is the position and the “un“ is the term
Again there are five numbers and they are holding the first five POSITIONS
The position simply represents the number of digits in a sequence, in the above there are "5" [ 3(which is 1), 6(which is 2), 11(which is 3), 18(which is 4), 27( finally this is number 5 )]
(Position) U 1 2 3 4 5
( Term) Un 3 6 11 18 27
n2=(n x n) 1 4 9 16 25
So what exactly is the connection (the pattern ) between the "n" and the "un", in this question?
Is there a set pattern?
Are they going up in 2's or 4's? --- NO they are not!
3 + 3 = 6
6 + 5 = 11
11 + 7 = 18
18 + 9 = 27
In a case like this we would square (n2) the numbers and see what that brings us too.
Therefore we can write down that un = n2 (which means n x n)
1 x 1 = 1
2 x 2 = 4
3 x 3 = 9
4 x 4 = 16
5 x 5 = 25
These are the numbers we have got after multiplying n x n, you will have noticed that they are 2 less in each case than the numbers in the un term, therefore we need to add 2 in the formula.
Our formula now looks like this; un = n2 + 2 ( where the un is the nth term)
n x n = ? + 2 = un
1 x 1 = 1 + 2 = 3
2 x 2 = 4 + 2 = 6
3 x 3 = 9 + 2 = 11
4 x 4 = 16 + 2 = 18
5 x 5 = 25 + 2 = 27
Answer:- un = n2 + 2
Another favourite question in exams is as follows;
The nth term of a sequence is represented by this formula:- un = 3n + 2
We are asked to;
(i) Find the first 4 terms
(ii) To find the 49th term
( i ) Find the first 4 terms
Our formula is:- 3n + 2 = un
Therefore our 1st term is u1 = 3 x 1 = 3 + 2 = 5
2nd term u2 = 3 x 2 = 6 + 2 = 8
3rd term u3 = 3 x 3 = 9 + 2 = 11
4th term u4 = 3 x 4 = 12 + 2 = 14
Our first four terms are; u1 , u2 , u3 , and u4
They end up as 5, 8, 11, and 14
\ First 4 terms are: 5, 8, 11, 14. (Answer:-)
( ii ) We have been asked to find the 49th term.
49th term: This will be known as u49
As before in part ( i ) the formula is; un = 3n + 2
Therefore we will replace the “n” with the 49
un = 3n + 2
u49 = (3 x 49) = 147 + 2 = 149
(Answer) u49 = 149
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Really good one,very neatly explained with relevent examples
Same way you can postAP.,g.P. and H.P. also. I like it.
whats the first five sequences of this nth term, 3n + 4?
7, 10, 13, 16, 19 :)
What about the nth term for 1,2,4,8,15,26,42... It goes up in 1,2,4,7,11,16 and that goes up in 1,2,3,4,5 please post back quickly, all I can work out is how to find what it goes up in innitially the formulae for that is as follows: Xn= n(n-1)/2+1 can't find how to make the actual original sequence.
what is nth term for squared numbers
whaat is the nth term of 4 6 8 10
What is the nth term of this sequnce 5 10 15 20 25
what will be the nth term for 1, 12, 24, 36, 48
how about this one. find the 9th term
n2/n+1
find a formula for 95, 90, 85,80
interms of n
gd website
what will be the nth term in this sequence
2,3,6,7,10,11......
Help!!!
What is the nth term in the sequence 107,68,29,-10,-49???pease help
me!!!
tn=a(r^(n-1))
where:
tn = general term
a = first term
r = common ratio
n = position of the term
if Tn=5-3n then find Tn+1 and Tn+2
whats the first five sequences of this nth term, 3n + 4?
Megan Please use the following;
3n + 4
3 x 1 = 3 + 4 = 7
3 x 2 = 6 + 4 = 10
3 x 3 = 9 + 4 = 13
3 x 4 = 12 + 4 = 16
3 x 5 = 15 + 4 = 19
Thankyou Empeen just trying to help.
Shweta,
if Tn=5-3n then find Tn+1 and Tn+2
Tn=5-3n
then T(n + 1) = 5 - 3(n + 1)
= 5 - 3n - 3
= -3n + 2
So Tn + 1 = -3n + 2 (Ans)
And Tn +2 = 5 - 3(n + 2)
= 5 - 3n - 6
= - 3n - 1
So Tn + 2 = - 3n - 1 (Ans)
JK,
What is the nth term in the sequence 107,68,29,-10,-49?
Tn = a + (n - 1) d
a = 107
d = 68 - 107 = -39
Tn = 107 + (n - 1) x -39
...= 107 - 39n + 39
...= 146 - 39n (Ans)
Ronak,
what will be the nth term for 1, 12, 24, 36, 48
a = 1
d = 12
Tn = 1 + (n - 1) x 12
....= 1 + 12n - 12
....= 12n - 11
......12n - 11 is the nth term
Eivlys
find the 9th term n2/n+1
Tn = n2 / n + 1
....= 9squared / 9 + 1
....= 81 / 10
....= 8.1 (Ans)
Raz,
find a formula for 95, 90, 85,80 in terms of n
Tn = a + (n - 1) x d
..a = 95
..d = 90 - 95 = -5
Tn = 95 + (n - 1) x -5
....= 95 - 5n + 5
....= 100 - 5n (Ans)
,.jnmkl.jh
(Position) U 1 2 3 4 5
( Term) Un 5 10 15 20 25
..n x 5
Therefore we can write down that un = 5n
U1 = 5 = 5 x 1
U2 = 10 = 5 x 2
U3 = 15 = 5 x 3
U4 = 20 = 5 x 4
U5 = 25 = 5 x 5
un = n x 5 = 5n
(Ans) un = 5n
dana,
(Position) U 1 2 3 4
( Term) Un 4 6 8 10
n x 2
4 + 2 = 6
6 + 2 = 8
8 + 2 = 10
Therefore we can write down that un = 2n
Looking again we may need to adjust that 2n slightly;
2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
These are the numbers we have got after multiplying n x 2, you will have noticed that they are 2 less in each case than the numbers in the un bracket, therefore we need to add on 2 in the formula.
Our formula now looks like this un = 2n + 2 (where the un is the nth term)
2 x n = ? + 1 = un
2 x 1 = 2 + 2 = 4
2 x 2 = 4 + 2 = 6
2 x 3 = 6 + 2 = 8
2 x 4 = 8 + 2 = 10
Answer:- un = 2n + 2
Bubble,
U 1 2 3 4
Un 3 4 6 9
U1 = 3
U2 = 3 + (2-1) = 4
U3 = 4 + (3-1) = 6
U4 = 6 + (4-1) = 9
So Un = U(n-1) + (n-1)
Hope this helps
Bubble,
U 1 2 3 4
Un 3 4 6 9
U1 = 3
U2 = 3 + (2-1) = 4
U3 = 4 + (3-1) = 6
U4 = 6 + (4-1) = 9
So Un = U(n-1) + (n-1)
Hope this helps
For further help follow the link in the hub "Let me solve your maths problems". Assistance can be found for
Bodmas
HCF
LCM
Prime and Composite numbers
Square Root
Cube Root
Place Values
Expanded Notation
Rounding off Numbers
Writing numbers as a product of their Prime Numbers
Irshad,
This is just an ordinary sequence(not an arithematic one) The values go upwards in differences of 1's and 3's.
2 3 6 7 10 11
--- --- --- --- --- (Difference is)
1 3 1 3 1
so at some point in a sequence like this values would be ommitted and you would have to find them.
I really found this helpful. Please help me find the nth term of the sequence 1 , -2 , 3, -4,.... Thanks.
Ema,
In answer to your equation 1, -2, 3, -4;
This is not an arithematical sequence nor is it a geometric one, it is a general sequence that is alternating.
In this question "d" is not unique;
t2-t1 = -2 -1 = -3
t3-t2 = 3 -(-2) = 3 + 2 = 5
So the answer to this sequence is;
nth term is -n (if "n" is even)
............+n (if "n" is odd)
Hope this helps, thanks
Telia
please help,
i'm trying to work out the nth term for the following:
5 8 11 14
i know there's three difference between each number, but i'm getting confused as how to work this out...
thanks :)
Nico,
(Position) U..1....2....3....4
( Term).......5....8....11...14
you are correct the common difference(d) is "3"
This tell you that your formula is going to start with "3n"
Therefore;
Go back to your table and put in your values in the 3n formula and see what else is required to solve it.
d x u
3 x 1 = 3 + ? = 5
3 x 2 = 6 + ? = 8
By now you'll see that you need to add on 2
So your formula is going to be 3n + 2
un = 3n + 2 (where the un is the nth term)
Oli.
(i) 1, 2, 4, 8
Firstly we will put these values into a table
n 1 2 3 4
un 1 2 4 8
? ? ? (now to find the differences)
1 2 4 (The number is being doubled each time, this suggests that the rule
involves 2 to the power of something.)
un = ?
un = 2n
This time the formula involves subtraction of the power
Therefore; un = 2n - 1
21 - 1 = n0 = 20 which equals 1
22 - 1 = n1 = 21 which equals 2
23 - 1 = n2 = 22 which equals 4
24 - 1 = n3 = 23 which equals 8
if you check back to the above table the formula is correct
un = 2n - 1
That answer is 2 (to the power of n - 1)
Telia
can you find the rule for the nth term for the following sequence on numbers?
5,27,79,173
ive looked at it for a bit and i can only come up with this rule, which only works for the first 3 numbers:
6n^4/2n - n^n-1 +5
Pien,
The rule you are looking for is
2n^3 + 3n^2 - (n - 1)
Hope this helps
let 1,3,2,5......find 6th term
The 6th term in this sequence is 7.
5th is 3
Some comments are not satisfactory. Also in many cases only nth term rule is given. how can we find the process?
Krishnasingh
If you read through the above hub observing and understanding the tables you'll be able to follow the process to find the nth term.
Say your common difference is 4
then you are working with 4n plus or minus something to find the rest of your formula to solve the equation.
It takes a little bit of patience and practise.
If there is no visible difference then try squaring the numbers in the "u" bracket and find out what else you have to add or subtract to find the formula.
Please read over the worked examples again and you'll see not only is the nth term rule there but so is the process.
Good Luck
What is the ninth term in the following sequence? 6, 10, 14, 18, 22,...
Bubba,
First start by finding the nth term.
Your difference is 4 so that tells you the formula is going to start as 4n + or - something.
So do out your table as shown in the worked examples above
...1...2...3...4...5
...6..10..14..18..22
4 x 1 = 4 + ? = 6 (? = 2)
4 x 2 = 8 + 2 = 10
4 x 3 = 12 + 2 = 14
So the formula is 4n + 2
Now use the formula to find the 9th term
U(9) = 4 x 9 = 36
36 + 2 = 38
Therefore 9th term = 38
Hope this helps.
what is the nth sequence of 1,4,12,32,80
Rix
Im not finding a common difference here have you wrote this question down properly? Please check
What is the rule of this sequence? 23, 19, 13, 8
what would be the nth term for the sequence 0,6,14,24,36,50
??????
Georgia,
Your question dosen't follow any rule have you wrote it down properly?
Ema,
tn = 6, 8, 10, 12, 14
a = 6
d = 2
tn = a + (n-1) 2
tn = a + 2n - 2
The nth term your looking for EMA is
tn = 2n + 4
what is the next term of 1,6,4,9,7
Elias,
1..6..4..9..7..12..10
what is the first five terms for the nth term of 16-3n
Jordan,
16 - (3 x 1) = 13
16 - (3 x 2) = 10
16 - (3 x 3) = 7
16 - (3 x 4) = 4
16 - (3 x 5) = 1
So first five terms are as follows
13..10..7..4..1
two terms of an arithmetic sequence are a8=76 and a28=296 whats the rule for the nth term?
Hi ari h,
an = a + (n - 1) d
now put in n = 8, an = 76
76 = a + (8 - 1) d
76 = a + 7d (equation 1)
an = a + (n - 1) d
now put n = 28, an = 296
296 + a + (28 - 1) d
296 = a + 27d ( equation 2)
Take the equations away from each other
296 = a + 27d
76 = a + 7d
--------------
220 = 20d
Then find common denominator and cancel down.
20d = 220
-----------
20 20 (CANCEL DOWN)
The two 20's cancel each other leaving "d" on its own on the left hand side of the equation.
On the right hand side of the equation 20 divides into 220 = 11
Therefore d = 11
a + 7d = 76
d = 11
a + 7 (11) = 76
a + 77 = 76
a = -1
Therefore a = -1, d = 11
Last Step in this Equation;
an = a + (n - 1) d
an = -1 + (n - 1) 11
an = -1 + 11n - 11
an = 11n - 12
So the nth term for a8 = 76 and a28 = 296 is;
an = 11n - 12
Hope this helps.
This site is cool but it would be cooler if you added this place which says want to find out the nth term of something type it in here and you will get your answer
Thanks Humaira Patel,
I will always answer irrespective of the fact that sometimes the question might not be asked in the correct hub. I am always glad when a student shows enough intution to ask a question if they are stuck or unsure of something.
Help please how is this worked out
first term 4 term to term rule x3 +1
Tom,
un = 3x + 1
.....3 x 1 = 3 + 1 = 4
.....3 x 2 = 6 + 1 = 7
.....3 x 3 = 9 + 1 = 10 etc
Hope this helps
I am stuck with this question. please help me out.
5A(n+1) + 1 = 5A(n) + n
Given A(5)=55. Find A(55)
I am using the brackets to denote that the numbers in the brackets are at the base. i.e A(n+1) denotes n+1 th term.
Hi Varsha,
Using the brackets to denote that the numbers in the brackets are at the base.
5A(n + 1) + 1 = 5A(n) + n
Given A(5) = 55
.......A(55) = ?
5A(n + 1) + 1 = 5A(n) + n
Take the 1 over the = sign to the other side and it becomes -1 (change side ,change sign)
5A(n + 1) = 5A(n) + n - 1
Now divide each side by 5 to get A(n + 1) on its own;
Therefore
A(n + 1) = 5A(n)/5 + (n - 1 /5)
The 5's cancel each other out and your left with the formula;
A(n + 1) = A(n) + (n - 1 / 5)
So use this formula to solve A(55)
We know A(5) = 55
So we will find A(6)....up til A(55)
This will have to be done manually as the difference is 0.2 and it is compoundly added on to the next total. OK so far!
So lets take the Formula we found and start plugging in the values to solve this equation.
A(n + 1) = A(n) + (n - 1 / 5)
A(5) = 55
A(5 + 1) = A(5) + (5 - 1 / 5)
.........= A(5) + (4 / 5)
.........= 55 + 0.8 = 55.8
_________________________________________________________
A(6 + 1) = A(6) + (6 - 1 / 5)
.........= A(6) + (5 / 5)
.........= 55.8 + 1 = 56.8
_________________________________________________________
A(7 + 1) = A(7) + (7 - 1 / 5)
.........= A(7) + (6 / 5)
.........= 56.8 + 1.2 = 58
and so on until
A(54 + 1) = A(54) + (54 - 1 / 5)
.........= A(54) + (53 / 5)
.........= 329 + 10.6 = 339.6
At the start of this equation I was able to find the (n - 1 / 5) to be 10.6 but had to do the whole equation manually to find the 339.6 value.
Therefore A(55) = 339.6
Hope this helps
Thank you for your quick response.
Sorry to bother you again ...but require one clarification...
Did you calculate every term to arrive to A(55)or you calculated it directly by some formula. i.e how you got A(54) as 329?
Hi Varsha,
Sorry but there is no Formula for this aspect of the equation - each term has to be calculated individually to arrive at A(55).
Is this a homework question?
I am giving some entrance exam. This was one of the question in the mock test which has a time constraint. Anyways will have to skip such questions as they are too time consuming or will have to search some better method for solving this.
Thank you for your response.
Hi Varsha,
If you practice this question you should be ok, but please don't skip it as this is one of the question which would seperate the "men from the boys" so to speak. The first part of this question is relevantly straight forward- do that then come back to finish it, this will show them you know what you are doing. It seperates the "A" students from the "C" students. Good Luck
Hi
Was trying for long to find some different method to solve this. Check this out....
Using {} these brackets to denote the actual brackets.
5A(n + 1) + 1 = 5A(n) + n
A(n+1) = A(n) + 1/5 {n-1}
A(6)= A(5)+ 1/5 {5-1}
....= 55 + 1/5 {4}
Similarly A(7) = A(6)+ 1/5{6-1}
.... = 55 + 1/5 {5} + 1/5 {4}
.... = 55 + 1/5 {4 + 5}
So A(55) = 55 + 1/5 {4+5+6+7......+52+53}
... = 55 + 1/5 {53x54/2 - {3+2+1}
... = 55 + 1/5 {1431 -6}
... = 55 + 285
... = 340
which is close to 339.6
What is your opinion? Is this a correct method?
Hi Varsha,
Sorry for the delay was out.
OK here goes , I made a slight mistake of 0.4 at the A(40) part of this equation for that I apologise. The answer should have been 202 at that point and not 201.6 as I had noted in my notepad.
As a result after plugging in your idea I have got this to work as per your answer,
A(n + 1) = A(n) + [n - 1 / 5] + d
...........A(55) + [4+5+6+7+8+9....+53 - 1 / 5] + d
...........A(55) = [1425 - 1 / 5] + 0.2
..................284.8 + 0.2 = 285
..................285 + 55 = 340
0.2 being the difference each time
Absolutely brilliant Varsha
Good Luck
Although we come up with a formula Varsha you still need to work out the first 3 or 4 terms manually to see if there is any correlation within the problem.
My idea was to find the first term of the series and then using the Arithmatic progression formula to find the value of A(55) - for that the difference between two terms has to be constant - so we don’t have a choice here but to do it manually:(
If you work out a few more of them you will find you are always adding 55 at the end in the equation plus the difference of 0.2
Good Luck with the entrance exam.
Ya dats true.. Will have to do that much of calculations...No other option :(
Anyways, Thanks a lot.
Sorry but will keep on bothering you till my exams.
Hi Varsha,
Glad to be of a help to you and keep in contact - if you need anything else clarified before your exam don't hesitate to contact me.
Good Luck in your exam studies.
whats is the nth term for 38, 33, 28, 23, 18
and 640, 320, 160, 80 I',m having a hard time with this thank you
Hi,
Had put this question in your trigonometric forum. But not got any reply yet.waiting for your response.
"Need i more help from you.
I tried searching sin theta table for multiples of 5 on internet which is in fractions. Like sin theta 75 degree, 80 degree etc in fractions. But the search showed sin theta table in decimals. Do you have one with fractions?
My purpose is to learn these fractions so as to answer area of triangle questions by the 1/2 ab sin theta formula, where a & b are the sides and theta is the angle between them.
Also are there any other trigonometric formulas for finding areas of geometric figures?"
please help me on this one pleaseeeeeeeeeeeeeeeeee.
i really need to know this today and right now b4 i go off..
what's the first 4 terms of the number sequence using the nth term rule which is: N3+3 ???
the first number 3 is actually supposed to be over the n and small...
SSSS,
Do you mean N cubed + 3
If so then,
1 x 1 x 1 = 1 + 3 = 4
2 x 2 x 2 = 8 + 3 = 11
3 x 3 x 3 = 27 + 3 = 30
4 x 4 x 4 = 64 + 3 = 67
Please clarify if this is correct
Sheena,
tn = a + (n - 1) d
a = 38
d = -5
tn = 38 + (n - 1) -5
tn = 38 -5n + 5
tn = 43 - 5n (answer)
In the next one the sequence is
640,...320,...160,...80
1st term = 640
2nd term = 320 = 640 / 2 = 1st term / 2
3rd term = 160 = 320 / 2 = 2nd term / 2
4th term = 80 = 160 / 2 = 3rd term / 2
so we can say
nth term = n - 1 / 2
(n - 1)th term is previous to nth term
Varsha,
When
theta is 0...sin theta is 0
theta is 30 degrees...sin theta is 1/2
theta is 45 degrees...sin theta is 1/squareroot 2
theta is 60 degrees...sin theta is squareroot 3 / 2
theta is 90 degrees...sin theta is 1
theta is 120 degrees...sin theta is sq root 3 / 2
theta is 135 degrees...sin theta is sq root 2 / 2
theta is 150 degrees...sin theta is 1 / 2
theta is 180 degrees...sin theta is 0
theta is 210 degrees...sin theta is -1 / sq root 2
theta is 225 degrees...sin theta is -sq root 2 / 2
theta is 240 degrees...sin theta -sq root 3 / 2
theta is 270 degrees...sin theta is -1
theta is 300 degrees...sin theta is - sq root 3 / 2
theta is 315 degrees...sin theta is - sq root 2 / 2
theta is 330 degrees...sin theta is -1 / 2
theta is 360 degrees...sin theta is 0
Hope this helps Varsha
Thanks a lot..
does this sequence diverge or converge, and if it converges, what is the limit?
(2n+1)/(1-3sqrt(n))?? thanks
wow !
what is the nth term of the sequence 6,14,24,36? is it a quadratic?
what is the general term of 1,2,7,11,16,22? thank you
Is there any technique to get the general terms? plsss help me. huuuh. thank you.
Here's a weird one we can't figure out:
0, 2, 4, 8, 24, 220
What's the next term and rule? I need to figure the first 12 terms. Pls answer to ahofer@nstsystems.com if possible.
help me plsss.. our final exam is coming up.. can you help for the general term of this no. 3,3,6,6,9,9,12,12 thanks in advance
Hi Mike.
Sorry about the delay in answering your question but Ive been very busy. Now to get caught up!
This sequence diverges.
(2n + 1) / (1 - 3 sqrt n)
rationalise the denominator
(2n + 1) ( 1 + 3 sqrt n) / (1 - 3 sqrt n)(1 + 3 sqrt n)
= (2n + 1) (1 + 3 sqrt n) / 1 - 9n
= 2n + 2n.3 sqrt n + 1 + 3 sqrt n / 1 - 9n
= 2n + 6(n)to the power 3/2 + 1 + 3 sqrt n
Divide each term by the highest power of n
(e.g) (n to the power of 3/2)
= 2n / n to the power 3/2 + 6n to the power 3/2 / n to the power 3/2 + 1 / n to the power 3/2 + 3 sqrt n / n to the power of 3/2 all over 1 / n to the power 3/2 - 9n / n to the power of 3/2
= 2 / n to the power of 1/2 + 6 + 1 / n to the power of 3/2 + 3 / n squared, all over 1 / n to the power of 3/2 - 9 / n to the power 1/2
put the limit n arrow infinity (use sign for infinity which looks like an eight sideways)
= 2 / infinity + 6 + 1 / infinity + 3 / infinity all over 1 / infinity - 9 / infinity
= 0 + 6 + 0 + 0 / 0 - 0
= 6 / 0
= infinity
Therefore the limit of this sequence is infinity and clearly this is a diverging sequence.
Hope this helps and Good Luck.
Hi Sebastian,
what is the nth term of the sequence 6,14,24,36? is it a quadratic? NO
6 = 6 x 1 = (6 + 1) x (1 + 1)
14 = 7 x 2 = (6 + 2) x ( 1 + 2)
24 = 8 x 3 = (6 + 3) x ( 1 + 3)
36 = 9 x 4
so nth term {6 + (n - 1)} x {1 + (n - 1)}
...........= (6 + n - 1) (1 + n - 1)
...........= (n + 5)(n)
...........= n squared + 5n
Hope this helps and good luck
Hi Michael,
what is the general term of 1,2,7,11,16,22?
The pattern is as follows;
1 + 0 = 1
1 + 1 = 2
2 + 2 = 4
4 + 3 = 7
7 + 4 = 11
11 + 5 = 16
16 + 6 = 22
22 + 7 = 29
So next term is 29 ( 8th term = 29)
9th term = 8th term + 8
..........29 + 8 = 37
Therefore the general term is;
Term (n + 1) = Term (n) + n
T (n + 1) = T (n) + n
Hope this helps, Good Luck
There is no magic formula for working out sequences except work out their pattern, tedious as it is.
Hi MichaelneLa,
can you help for the general term of this no. 3,3,6,6,9,9,12,12
Series questions are set out like this double 3's, double 6's etc so general term is 3n + 3, 3n + 3
3 x 1 = 3 + 3 = 6
3 x 2 = 6 + 3 = 9
3 x 3 = 9 + 3 = 12
Term you are looking is 3n + 3
Hope this helps and Good Luck
Hi Caroll,
What's the nth term of 1, 1/2, 3, 1/4, 5, 1/6, 7, 1/8, 9, 1/10, 11
From the above sequence the 9th term is 9
The sequence is found out by the following method;
Every odd number increases by 2
First term = 1
Third term = 3 etc
Whereas 2 is being added to the demoninator each time to get the next even term.
nth term is;
= 1 + (n - 1) 2
= 1 + 2n - 2
= 2n - 1
Therefore 2n - 1 is the nth term for odd terms.
For the even terms 1/2, 1/4, 1/6, the nth term is 1/(2n)
that is written as a fraction 1 over 2n
Hope that helps and Good Luck
nive post. really helped.
what is the nth term of 6, 8, 10, 12, 14, 16... ??
Please help meee :(
t.elia: Your solution (4 posts above mine) for "What's the nth term of 1, 1/2, 3, 1/4, 5, 1/6, 7, 1/8, 9, 1/10, 11" is incorrect. It should be n for odd numbers and 1/n for even.
Dear Jai,
Im sorry you have made a BIG mistake in your calculations. Please re-check them, not for my sake but for your own educational purposes.The answer you posted above is WRONG!
My Calculations are CORRECT
The answer for the workings of the nth term of this equation are as I stated;
Therefore 2n - 1 is the nth term for odd terms.
For the even terms 1/2, 1/4, 1/6, the nth term is 1/(2n)
that is written as a fraction 1 over 2n
Many Thanks for the post
Telia
Hi Turkish,
The nth term you are looking for to solve this equation is;
2n + 4
Regards
Telia
What the nth term for 15,21,27,33,39
and 19,13,7,1,-5
rule of 14,23,32,41,50? and ule of 1,6,11,16,21 please1
thanks!
Hi lltbbas,
Tn = a + (n-1) d
a = 15
d = 21 - 15 = 6
Tn = 15 + (n-1) x 6
Tn = 15 + 6n - 6
Tn = 9 + 6n (ANS)
Now for the second one;
Tn = a + (n-1) d
a = 19
d = 13 - 19 = -6
Tn = 19 + (n-1) x -6
Tn = 19 - 6n + 6
Tn = 25 - 6n (ANS)
Good Luck
Hi ,
Here is the help you requested
Tn = a + (n-1) d
a = 14
d = 23 - 14 = 9
Tn = 14 + (n-1) x 9
Tn + 14 + 9n - 9
Tn = 5 + 9n (ANS)
The next one is;
Tn = a + (n-1) d
a = 1
d = 6 - 1 = 5
Tn = 1 + (n-1) x 5
Tn = 1 + 5n - 5
Tn = -4 + 5n (ANS)
Good Luck and hope this helps.
What is the 10th term of the Tn = n (n + 5)?
please help find the next three sequence
20,4,16,37
superb.................found it really helpful....
Dear Hafsa,
I never judge a book by its cover.
Telia
@rix
what is the nth sequence of 1,4,12,32,80
n.2^(n-1)
whta i the the nth term formula for 3,6,9,12,15,18 ......Please!!
Dear iamhappy,
Your common difference is 3, therefore this tells you to write down 3n
Now if you work it out using the layout of the tables at the start of this hub you will find the following;
3 x 1 = 3
3 x 2 = 6
3 x 3 = 9
3 x 4 = 12
so therefore your answer is 3n
Good luck
Hi chipcat,
3n + 4 what is the 8th term of this question?
3n = ( 3 x n)replace the "n" with the "8"
Therefore;
3 x n
3 x 8 = 24 + 4 = 28
So 8th term of this question is 28
What would the nth term of the sequence 1,13,37,73,... be? Can someone please explain with steps. Thank you!
Hi Daisy,
You need to follow this method to complete this math;
1, 13, 37,73.....
The general form of this sequence is;
an^2 + bn + c (^2 means squared)STEP 1 of this equation
Constant = 13 - 1 = 12
a = constant/2 (constant divided by 2) = 12 / 2 = 6
a = 6
Plug a = 6 into STEP 1
an^2 + bn + c (^2 means squared)STEP 1
6n^2 + bn + c (STEP 2 of this equation)
for n = 1
Next
6(1) + b(1) + c = 1
6 + b + c = 1
b + c = -5 (STEP 3 of this equation)
Now n = 2 in STEP 2
6(2)^2 + b(2) + c = 13
2 x 2 = 4 x 6 = 24
24 + 2b + c = 13
2b + c = -11 ( STEP 4)
STEP 3 = b + c = -5
STEP 4 = 2b + c = -11
(-) (-)
------------------------
= -b/-1 = 6/-1
Cancel down b= -6
Plug 6 = -6 (in @ STEP 3)
b + c = -5
-6 + c = -5
c = -5 + 6
c = 1
Plug a = 6, b = -6, & c = 1 (into STEP 1
an^2 + bn + c
Your Answer becomes
6n^2 - 6n + 1 ( Answer)
Good Luck...Hope this helps.
Hey! Thank you so much :) That helped a lot, its so clearly explained! Thanks again!
find the a8 for the sequence a1=-2, an=3a(n-1) +6
Hi hellp...
Given:-
a(1) = -2
an = 3a(1) (n - 1) + 6
Solution:-
an = 3a (n - 1) + 6
Plug n = 8 and a(1) = -2
a(8) = 3(-2) (8 - 1) + 6
a(8) = -6 (7) +6
a(8) = -6 x 7 + 6
a(8) = -42 + 6
a(8) = -36
Hope this helps & Good Luck
find the nth term for 1/5, 2/6, 3/7, 4/8, 5/9... ?
I can see the pattern but I'm not sure how to express it Help? :)
position: 1 2 3 4 5 6
value of : 5 14 23 32 ??
term
!!!!!!!HELP!!!!!!!
Unable to find the Expression for the sequence
3,6,18,36,108....
next number in the sequence is by multiplying it by 3 and 2 alternatively.
Thanks.
really helpfull
help me to solve this:
(28% - 8%) / 1.4 = ?
What is the nth term of the sequence 0,1,1,2,2,3,3,4,4,5,5......?
The nth term of a sequence is 100-2n
What is the 1st term, 15th term and 30th term?
hi what is the sequence and the result in nth term for these numbers please, 23, 16, 9, 2
Thanks
hi again i posted a minute ago also can you tell me what the rule is as well as the sequence and the result in nth term
thanks
whats the nth term of 4,8,16
I am looking at this pattern: 7,0,0,0...I need to find the next 2 numbers in the pattern and I can't even see the rule for the pattern. Can anyone help?
how do i get the first five numbers in the sequence when 34-5n is the nth term rule?
what is the nth term of pattern 20,44,76,116....
i know it is adding multiples of 8 each time
What is the formula for 1,2,3,4,5,6
11,9,7,5,3,1
I have an exam tommorow. Can you plz tell me the formula for: 20, 17, 14, 11, 8,
EXAM,
The formula you need to use to solve this equation is as follows;
Tn = a + (n - 1) d
Therefore
a = 20
d = 17
Take d away from a
17 - 20 = -3
Now plug the results into your formula;
Tn = a + (n - 1) d
...= 20 +(n - 1) -3 (multiply out the brackets)
...= 20 -3n + 3
...= 23 - 3n
This is your answer!!
Good Luck in your Exams tomorrow.
Arpita,
How to find the first 5 numbers in the sequence 34 - 5n
-5 x n
-5 x 1 = -5
.......= -5 + 34 = 29
-5 x 2 = -10
.......= -10 + 34 = 24
-5 x 3 = -15
.......= -15 + 34 = 19
-5 x 4 = -20
.......= -20 + 34 = 14
-5 x 5 = -25
.......= -25 + 34 = 9
So therefore the first 5 numbers in the sequence are ;
29 , 24 , 19 , 14 , 9
Good Luck hope you understand this.
MEGAN
The formula you need to use is;
Tn = a + (n - 1) d
a = 23
d = 16
16 - 23 = -7
Now plug the results into your formula;
Tn = 23 + (n - 1) d
Tn = 23 + (n - 1) -7 (multiply out the brackets)
...= 23 -7n + 7
...= 30 - 7n (nth term rule)
Therefore;
-7 x 1 = -7
.......= -7 + 30 = 23
-7 x 2 = -14
.......= -14 + 30 = 16
-7 x 3 = -21
.......= -21 + 30 = 9
-7 x 4 = -28
.......= -28 + 30 = 2
-7 x 5 = -35
.......= -35 + 30 = -5 etc
Good Luck
BROOKIE
Use the following formula;
Tn = a + (n - 1) d
a = 5
d = 14
14 - 5 = 9
Therefore plug the results into the formula as follows;
Tn = a + (n - 1) d
...= 5 + (n - 1) 9 (multiply out the brackets)
...= 5 + 9n - 9
...= -4 + 9n (This is your nth term rule)(ANSWER)
9 x (1) = 9 - 4 = 5
9 x (2) = 18 - 4 = 14
9 x (3) = 27 - 4 = 23
9 x (4) = 36 - 4 = 32
9 x (5) = 45 - 4 = 41 etc
Good Luck
NIKEE
The nth term of a sequence is 100-2n
What is the 1st term, 15th term and 30th term?
100-2n
First Term
2 x (1) = 2
100 - 2 = 98
Fifteenth Term
2 x (15) = 30
100 - 30 = 70
Thirtith Term
2 x (30) = 60
100 - 60 = 40
1st Term = 98
15th Term = 70
30th Term = 40
Good Luck
ROHIT
You need to follow this formula for the numbers 11,9,7,5,3,1
Tn = a + (n - 1) d
a = 11
d = 9
9 - 11 = -2
Tn = a + (n - 1) d
Tn = 11 + (n - 1) -2 (multiply out brackets)
Tn = 11 -2n = 2
...= 13 - 2n (ANSWER)( nth term rule)
Good Luck
what are the next 5 nth terms for 4n+4?!?!?!?!!?!?
thanks.
BOB
The next 5 terms for the nth term rule 4n + n are;
4 x (n) + 4
Term 1
4 x (1) = 4 + 4 = 8
Term 2
4 x (2) = 8 + 4 = 12
Term 3
4 x (3) = 12 + 4 = 16
Term 4
4 x (4) = 16 + 4 = 20
Term 5
4 x (5) = 20 + 4 = 24
Hope this helps
what would be the next 3 terms for o.25n+5 and the 10th term
QUADLET
I take it this is 0.25n + 5
Workings of First Term;
0.25n + 5
= 0.25 x (n) + 5
0.25 x (1) = 0.25 + 5 = 5.25 ( Ans)
Workings of Second Term;
0.25 x (2) = 0.50 + 5 = 5.5 ( Ans)
Workings of Third Term;
0.25 x (3) = 0.75 + 5 = 5.75 ( Ans)
Workings of Tenth Term;
0.25 x (10) = 2.5 = 5 = 7.5 ( Ans)
Good Luck
what will be the nth term for 95,90,85,80,75 ? please help, really appreciated :)
SOPHIE
For the sequence 95,90,85,80...
The formula you need to use is as follows;
Tn = a + (n - 1) d
a = 95
d = 90
90 - 95 = -5
Now plug this into your formula;
Tn = a + (n - 1) d
Tn = 95 + (n - 1) -5 (multiply out the brackets)
Tn = 95 -5n + 5
Tn = 100 - 5n ( Answer)
Prove answer:-
100 - 5n ( This means 5 multiplied by n)
100 - 5 x 1
100 - 5 = 95
Next
100 - 5n
100 - 5 x 2
100 - 10 = 90
etc
Good Luck
Hi please can you tell me the nth term for
36 42 48 54 60
-8 -3 2 7 12
1.2 1.4 1.6 1.8 2
how do you do like 5/12 = n/6
Hi please can you tell me the nth term for
36 42 48 54 60
-8 -3 2 7 12
1.2 1.4 1.6 1.8 2
Please can you tell me the sequence pattern for 3 15 35 63
Can you please tell me the sequence pattern for 2, 8, 14, 20 AND 8, 5, 2, -1 please??
Also can you give the answer for tomorrow (26 September)?
SAM
5/12 = n/6
You will need to cross multiply here
That will give you;
12n = 30
..n = 30/12 (Cancel Down by dividing by 6)
..n = 5/2
Good Luck
P
( 28% - 8%)/ 1.4
= (20%)/ 1.4
= 20 over 100/ 1.4
= 0.2/ 1.4
= 1/7 (Ans)
EMMA
the sequence pattern for 2, 8, 14, 20
Use the following formula;
Tn = a + (n - 1 ) d
a = 2
d = 8
8 - 2 = 6
Tn = a + (n - 1) d
...= 2 + (n - 1 )6
...= 2 + 6n - 6
...= 6n - 4 (Ans)
Prove your Answer;
6n - 4
6(1) - 4 = 6 - 4 = 2
6(2) - 4 = 12 - 4 = 8
6(3) - 4 = 18 - 4 = 14
6(4) - 4 = 24 - 4 = 20
Good Luck
EMMA
the sequence pattern for 8, 5, 2, -1
Use the following formula;
Tn = a + (n - 1 ) d
a = 8
d = 5
5 - 8 = -3
Tn = a + (n - 1 ) d
Tn = 8 + (n -1) -3
...= 8 - 3n + 3
...= -3n + 11 (Ans)
Prove your Answer;
-3n + 11
-3(1) + 11 = -3 + 11 = 8
-3(2) + 11 = -6 + 11 = 5
-3(3) + 11 = -9 + 11 = 2
-3(4) + 11 = -12 + 11 = -1
Good Luck
BILL
the nth term for 36,42,48,54,60
Use the following formula;
Tn = a + (n - 1 ) d
a = 36
d = 42
42 - 36 = 6
Tn = a + (n - 1 ) d
...= 36 + (n - 1) 6
...= 36 + 6n - 6
...= 30 + 6n (Ans)
Prove your Answer;
30 + 6n
6(1) + 30 = 6 + 30 = 36
6(2) + 30 = 12 + 30 = 42
6(3) + 30 = 18 + 30 + 48
6(4) + 30 = 24 + 30 = 54
6(5) + 30 = 30 + 30 = 60
Good Luck
BILL
the nth term for -8 -3 2 7 12
Use the following formula;
Tn = a + (n - 1 ) d
a = -8
d = -3
-3 - (-8) = 5
Tn = a + (n - 1 ) d
...= -8 + (n - 1) 5
...= -8 + 5n -5
...= -13 + 5n
Prove your Answer;
-13 + 5n
5(1) - 13 = 5 - 13 = -8
5(2) - 13 = 10 - 13 = -3
5(3) - 13 = 15 - 13 = 2
5(4) - 13 = 20 - 13 = 7
5(5) - 13 = 25 - 13 = 12
Good Luck
BILL
the nth term for 1.2,1.4,1.6,1.8,2
Use the following formula;
Tn = a + (n - 1 ) d
a = 1.2
d = 1.4
1.4 - 1.2 = 0.2
Tn = a + (n - 1 ) d
...= 1.2 + (n -1) 0.2
...= 1.2 + 0.2n - 0.2
...= 1 + 0.2n (Ans)
Prove your Answer;
1 + 0.2n
0.2(1) + 1 = 0.2 + 1 = 1.2
0.2(2) + 1 = 0.4 + 1 = 1.4
0.2(3) + 1 = 0.6 + 1 = 1.6
0.2(4) + 1 = 0.8 + 1 = 1.8
0.2(5) + 1 = 1.0 + 1 = 2.0 = 2
Good Luck
DELL336
the sequence pattern for 3 15 35 63
Sum of n terms = n/2 (2a + (n - 1) d )
Tn = 3 + 12 + 20 + 28... (add following term to get next number in sequence)
Tn = 3 + (n - 1/ 2) (2(12) + (n - 2) 8)
Tn = 3 + (n - 1/ 2) 24 + 8n -16
Tn = 3 + (n - 1/ 2) + 8n + 8
Tn = 3 + 8(n - 1 )(n + 1)/ 2
Tn = 3 + 4(n^2 - 1)
Tn = 3 + 4n^2 -4
Tn = 4n^2 - 1 (Ans)
PROVE YOUR aNSWER;
4n^2 - 1
4(1^2) - 1 = 4 - 1 + 3
4(2^2) - 1 = 16 - 1 = 15
4(3^2) - 1 = 36 - 1 = 35...
Good Luck
Please could u help me find the nth term for:
Q 1, 1/2, 1/8, 1/4, .....
this is the only part of the sequence i have sorry .
nth term formula for 8, 19, 34, 53, 76, 103
what is the formula of the sequence 10,8,5,1
What is are the next three terms for this sequence: 1,2,2,4,8
Im really confused!
MICHELLE,
The nth term for 1, 1/2, 1/4, 1/8...
1/2^0 = 1
1/2^1 = 1/2
1/2^2 = 1/4
1/2^3 = 1/8
1/2^4 = 1/16
Therefore;-
tn = 1/2^n-1
Good Luck
GEORGE,
nth term formula for 8, 19, 34, 53, 76, 103
The difference is 4 at the second level, letting you know you are dealing with a squared number in the answer.
tn = 2^n2 + 5n + 1 (Answer)
Good Luck
NEED HELP,
what is the formula of the sequence 10,8,5,1
Yn = X - n
yn = final term
n = number of terms
X = initial term
Explanation with Example
n = 2, X = 10
yn = x - n
....10 - 2 = 8
Yn = X - n (Answer)
Good Luck
OLIVER,
What is are the next three terms for this sequence: 1,2,2,4,8
1 x 2 = 2
2 x 2 = 4
2 x 4 = 8
1st term x 2nd term = Next term
4 x 8 = 32
8 x 32 = 8192
32 x 8192 = 262,2144
So Answer is 32,8192,2622144
Good Luck
ok i know this is random but if you start with 2 and double each time then what is the number if the nth term is n+3
then 105-5n
2n-0.5v
thanx
what are the first 5 nth term of 3n+6
What's the nth term for: -1 +1 -1 +1 -1.
Doing my GCSEs and stuck on homework.
Can somebody help me with the sequence of 1 8 9 12 please...are there 2 sequences? What follows after 12? Much appreciated!
WHAT IS THE FORMULA FOR tHIS SEQUENCE PLEAAAASE! 1 8 9 12
RUSS & ME,
Here is help with the sequence for your formula;
1 , 8 , 9 , 12
1^2, 2^3, 3^2 , (2*3*2) = 12
So the first number is squared = 1
...the second number is cubed = 8
...the third number is squared = 9
...the fourth is the powers multiplied (2*3*2) = 12
The fifth number will be 5^2 = 25
The sixth number will be 6^3 = 216
The seventh number is 7^2 = 49
The eighth will be the powers multiplied (2*3*2) = 12
and so on ......
Hope this helps
Good Luck
3,8,15,24,35 what is the rule for that? im stuck !
Excuse me, would you help me with 50,48,46,44 and 3,8,15,24,35 and 53,56,61,68 please, thanks.
DOM & DAVID,
you have both asked for the same problem here;
3, 8, 15, 24, 35
First difference is 5, 7, 9, 11
Second difference is 2
The Sum of the n terms is written as Sn and we know that the nth term = Tn = Sn - (Sn-1)
Tn = a + (n - 1) d
Tn = n/2 [ 2a + (n - 1) d ]
Tn = n/2 [ 2*3 + (n - 1) 2]
Tn = n/2 x 6 + n/2 x (n - 1)2 (cancel down)
Tn = 3n + n^2 - n
Tn = n^2 + 2n (Answer)
Good Luck
DAVID
50, 48, 46, 44
Tn = a + (n - 1) d
a = 50
d = 48
48 - 50 = -2
Tn = a + (n - 1) d
Tn = 50 + (n - 1) -2
Tn = 50 - 2n + 2
Tn = 52 - 2n (Answer)
Good Luck
DAVID
53, 56, 61, 68
first difference is 3, 5, 7
second difference is 2
Tn = a + (n - 1) d
The Sum of the n terms is written as Sn and we know that the nth term = Tn = Sn - (Sn-1)
Tn = 53 + 3 + 5 + 7
Tn = 53 + n/2[ 2*3 + (n - 1) 2]
Tn = 53 + n/2 x 6 + 2(n - 1) (Cancel down)
Tn = 53 + 3n + n^2 - n
Tn = n^2 + 2n + 53 (Answer)
Good Luck
Hi , You're smart , but all comments don't help me .
can you help me .
I have this sequence .
1 1 1 1 1 1 1 1 1 2
I want to calculate the 11st element and 12nd element
I want Math Equations .
I have a product gave me the answer but I want the way .
11st term = 11
12nd term = 56
please help me .
26-4n?
LIV
26-4n
26 - 4 x N
26 - 4 x (1) = 22
26 - 4 x (2) = 18
26 - 4 x (3) = 14 etc
Hope this helps
Good Luck
what would the answer be for the nth term for a sequence is n-2/ n squared
write the first three terms of the sequence
can you solv please 7,10,13,16
Oscar,
Answer is 3n + 4
3 x 1 = 3 + 4 = 7
3 x 2 = 6 + 4 = 10
3 x 3 = 9 + 4 = 13 etc
Good Luck & hope this helps
The value of (2/3)(3/4)(4/5).....(1-1/n)=
Hi, can you help me.
If i have these 4 numbers, 12 15 18 21, whats the sequente to get the nth term?
Hi Jamie
Your answer is 3n + 9
My homework sheet says that i have to write a rule in terms of n, i don't know what that means, the website for my homework is http://docs.google.com/viewer?a=v&q=cache:ap2taSTK/maths/docs/building_number_patterns.doc+building+investigative+skills&hl=en&gl=uk&pid=bl&srcid=ADGEESgdc2qKUJbnfZK9K6L22BqBGd27GIaVEhDj6m_QE5xBedMtgqj5QD7hfd1vx0armiQYpFn4mPs83vidpckpAmTdbMgP_2PR7u30s46xICSkUbnCcSq1TaTrXxr-ywh0FKdy2oaH&sig=AHIEtbScDxgftte_31i6WwekjrGnqCDRgA, i also don't get question 4
Hi Paul, this link you provided isn't working.
hello plaese help me find Recurrence Relations
t(n)=t(3n/5)+t(2n/5)+n
Ogleoo,
48 - 4n
48 - (4 x 1)= 48 - 4 = 44
48 - (4 x 2)= 48 - 8 = 40
48 - (4 x 3)= 48 - 12 = 36 etc
I hope you find this easy to follow
Good Luck
thank you so much
i keep forgetting that n means term number!!!
WHAT IS AP?
MAHI,
Arithematic Progression:-
A sequence of numbers. Let's start with a number: a1.
Now add a number d, (for "difference").
We get a1 + d and the first 2 terms in our sequence are:
a1, a1 + d
For the next term, let's add d to that last term and we have a1 + 2d.
Our sequence is now:
a1, a1 + d, a1 + 2d
We continue this process and the resulting set of numbers is called an arithmetic progression (AP) or arithmetic sequence
Good Luck Telia
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Simba,
What are you working on multiplication?? Please clarify.
Telia
Find the next term of the progression 24,12,8,.....
how do you find the equation and 50th term of 1,4,9,16,25,36,48
What is the nth term for this sequence (or similar ones): 2, 7, 15, 26. It goes up like this: +5, +8, +9.
Hi would you be able to help me with the general term (tn) I guess, I doesn't know the word in english... well here are the numbers, 2,7,15,26,40 thanks :)
Find the next term of the progression 2 4 6 14 23
0,2,4,6,8,12,12,20,16,?
answer is 12.
can u explain the trick behind this?
what would be the nth term of 40,38,36,34,32...
what would be the nth term of 30,28,26,24,22... and what would be the nth term of 40,37,34,31,28...
what would be the nth term of 30,28,26,24,22..
what is the nth term of 1+(1+2)+(1+2+3).....to n terms
I'm stuck on this question so could you help me out?
All terms in a geometric sequence are positive integers, and the first three ter4ms are n, n+3, and 2n+6. What is the fourth term of this sequence?
-1 , -2 , -1 , 2 , 7 , 14 whats the nth term please?
Whats The Next Three Terms of the Arithmetic Sequence?
6,12,18,24,__,___,___?
Help Please :D
what will be the next term for this series 2,3,4,7,13,12,12,23,20,17,33,28,? please help.
iam confuse between nth and n terms of A.P
PLEASE HELP T.ELIA
what will be the next term to the series 2,3,4,9,16... and how it will be???.....
the radiator of the truck contains 12 gallons of water. We draw off 3 gallons and replace it with alcohol, then we draw off 3 gallons of the mixture then replaced it by alcohol. until 8 drawings and replacements have been dine. How much alcohol is in the final mixture?
how bout sixth term of 3/4,3,12...
what is the formula of sixth term of 3/4,3,12...
and the tenth term of 0.4,0.04,0.004,,, plz give me a formula for this
how to find the 40 term of a sequance with term to term rule add 5and the 1st term of 6
5 x 4 x 3 ... -5 x -2 x - 4 Write out the correct form of the sequence
What is the Nth Term to: -1, 7, 18, 29, 42, 57
and 2, 9, 18, 29, 42, 57?
Please help!
given the general form an^2+bn+c
find a
pls help with the above
What is 2-3G and 7-1/2n??? I'm really confused and it's annoying me please answer tonight xxxx
The nth term of a sequence is the l.c.m of integers from 1 to n. Which term of the sequence is the first one that's divisible by 100?
what is the 75th term 8, 14, 20, 26, 32
plz find the indicated term of the following,1,3/2,5/4,7/8,...a7.
terms: 1,2,3,4,5,...n
values: 1,2,4,8,16,...
please find me the formula?
Can Anyone Find What's The 6th Term For 5 , 7 , 11 ....
in an AP the fifth term is 8 and the nineth term is 14. fin the first term.
WHAT IS THE FORMULER FOR THE SEQUENCE; 22,18,14,10?
Greetings ;)
What is the formula for the sequence 16, 29, 48, 52, 54 and 5 ?
Maa''m i can't understand general term.. I don't knw why.. If u can help me in dis.. it will be a great help..
-2,4,-8,16.. can u help me 2 find da general term of dis set??
a series is s
uch that the sum of the first nth therms is 2n^2 minus 3n.
1.how to Prove that the series is arithmatic
2.find the value of the 18th term
nth term of sequence ?7, ?21, 3?7.....
HI,
pleasssssssse solve this problem ,i am not getting the solution anywhere in the net.
"the sum of the first n terms of an ap are in the ratio (3n +8):(7n + 15), find the ratio of the 3 rd terms" ans 23:50.
HI,
pleasssssssse solve this problem ,i am not getting the SOLUTION anywhere in the net.
"the sum of the first n terms of an ap are in the ratio (3n +8):(7n + 15), find the ratio of the 3 rd terms"
{ans=23:50}.
nth term of sequence the sequence is 4, 12, 24
This is what i gett
4 12 24 40
\ / \ / \ /
8 12 16
\ / \ /
4 4
But I dont know how to make a formula from this help
give solution to this sum
sum of the series 2+4(3*3)+6(5*5)+.........+22(21*21)
if the sum of 4 consecutive terms in a gp is 60 and if the t1,18,t4 are in ap find the terms
ans(4,8,16,18)
what is the missing number in the following series
9,19,40,___,146?
trying to find out the correct sequence for if n+1/3
how to solve this
U 1 2 3 4 5
Un 1 4 10 22 46
plz define in detail what do we do with sequences not having a common difference E.G 0..-1..-8..-27..-64.
And also do you happen to know any formula like
Tn= A+d(n-1)+ 1/2[(n-1)(n-2)c] which claims to work on everything. If Yes than please explain the formula.
hi am year 7 what is the 5 terms and the 10th term of 2n+2
In the sequence, 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 when we add any three numbers we have to get the answer 30
24 24 28 46 94 what is the next sequence
An arithmetic sequence has first term a=6 and common difference d=12. How many terms of this sequence must be added to get 5040?
Bubble 2 years ago
what would be the nth term for 3,4,6,9...?